2[t-(2t+18)+17]=2(t+1)

Solution for 2[t-(2t+18)+17]=2(t+1) equation:

Simplifying
2[t + -1(2t + 18) + 17] = 2(t + 1)

Reorder the terms:
2[t + -1(18 + 2t) + 17] = 2(t + 1)
2[t + (18 * -1 + 2t * -1) + 17] = 2(t + 1)
2[t + (-18 + -2t) + 17] = 2(t + 1)

Reorder the terms:
2[-18 + 17 + t + -2t] = 2(t + 1)

Combine like terms: -18 + 17 = -1
2[-1 + t + -2t] = 2(t + 1)

Combine like terms: t + -2t = -1t
2[-1 + -1t] = 2(t + 1)
[-1 * 2 + -1t * 2] = 2(t + 1)
[-2 + -2t] = 2(t + 1)

Reorder the terms:
-2 + -2t = 2(1 + t)
-2 + -2t = (1 * 2 + t * 2)
-2 + -2t = (2 + 2t)

Solving
-2 + -2t = 2 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-2 + -2t + -2t = 2 + 2t + -2t

Combine like terms: -2t + -2t = -4t
-2 + -4t = 2 + 2t + -2t

Combine like terms: 2t + -2t = 0
-2 + -4t = 2 + 0
-2 + -4t = 2

Add '2' to each side of the equation.
-2 + 2 + -4t = 2 + 2

Combine like terms: -2 + 2 = 0
0 + -4t = 2 + 2
-4t = 2 + 2

Combine like terms: 2 + 2 = 4
-4t = 4

Divide each side by '-4'.
t = -1

Simplifying
t = -1